From: Chad Thompson <chad@weblinkservices.com>
To: Dan Langille <dan@langille.org>
Cc: pgsql-sql@postgresql.org
Subject: Re: 7.3 "group by" issue
Date: Fri, 21 Feb 2003 13:51:35 -0700
Message-ID: <053901c2d9eb$0cd85000$32021aac@chad> (raw)
References: <3E5649A9.26494.1F008FD6@localhost>
> On 21 Feb 2003 at 13:30, Chad Thompson wrote:
>
> > The same applies to group by... Sorry for the confusion.
> >
> > If the column is not in the select section of the statement, it cant
group
> > by it.
> > Try this.
> >
> > SELECT element_id as wle_element_id, COUNT(watch_list_id)
> > FROM watch_list JOIN watch_list_element
> > ON watch_list.id = watch_list_element.watch_list_id
> > WHERE
> > watch_list.user_id = 1
> > GROUP BY wle_element_id
>
> Yes, that works. But so do these.
>
> SELECT watch_list_element.element_id as wle_element_id,
> COUNT(watch_list_id)
> FROM watch_list JOIN watch_list_element
> ON watch_list.id = watch_list_element.watch_list_id
> WHERE
> watch_list.user_id = 1
> GROUP BY watch_list_element.element_id
>
>
> SELECT element_id as wle_element_id, COUNT(watch_list_id)
> FROM watch_list JOIN watch_list_element
> ON watch_list.id = watch_list_element.watch_list_id
> WHERE
> watch_list.user_id = 1
> GROUP BY element_id
>
> The original situation which did not work is:
>
> SELECT watch_list_element.element_id as wle_element_id,
> COUNT(watch_list_id)
> FROM watch_list JOIN watch_list_element
> ON watch_list.id = watch_list_element.watch_list_id
> WHERE
> watch_list.user_id = 1
> GROUP BY element_id
>
> My question: why should it not work? It's referring to the same
> column as the previous two examples which do work.
> --
I see the distinction you are making.
Maybe Tom or Josh could throw out a better answer, but I think that youve
called it one thing in your select and tried to group by it using a
syntaticly different name.
Any one have any other ideas?
Chad
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To: pgsql-sql@postgresql.org
Cc: chad@weblinkservices.com, dan@langille.org
Subject: Re: 7.3 "group by" issue
In-Reply-To: <053901c2d9eb$0cd85000$32021aac@chad>
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