From: Josh Berkus <josh@agliodbs.com>
To: Mathieu Arnold <m@mat.cc>
To: pgsql-sql@postgresql.org
Subject: Re: problem with subselect
Date: Fri, 7 Mar 2003 09:48:45 -0800
Message-ID: <200303070948.45070.josh@agliodbs.com> (raw)
In-Reply-To: <2063882566.1047045882@andromede.reaumur.absolight.net>
References: <2063882566.1047045882@andromede.reaumur.absolight.net>
Mathieu,
> SELECT date_trunc('month', f.date_creation) as mois,
> sum(f.montant_ttc / d.taux) as facture,
> (SELECT sum(f2.montant_ttc / d2.taux) as facture2
> FROM facture AS f2 JOIN devise AS d2 USING (id_devise)
> WHERE date_trunc('month', f2.date_creation)
> <= date_trunc('month', f.date_creation))
> FROM facture AS f JOIN devise AS d USING (id_devise)
> GROUP BY date_trunc('month', f.date_creation)
> "Sub-SELECT uses un-GROUPed attribute f.date_creation from outer query"
> Which is not really true, but some way is...
Hmmm ... this looks like a minor parser bug. What Postgres version are you
using?
> What I want is to get the sum of the month, and the sum of the month and
> the previous.
>
> If someone has a clue, something, anything... :)
Sure. Try putting the sub-select in the FROM clause, instead of the SELECT;
that should un-confuse the parser about the grouping.
--
Josh Berkus
Aglio Database Solutions
San Francisco
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To: pgsql-sql@postgresql.org
Cc: josh@agliodbs.com, m@mat.cc
Subject: Re: problem with subselect
In-Reply-To: <200303070948.45070.josh@agliodbs.com>
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