From: Stephan Szabo <sszabo@megazone.bigpanda.com>
To: Joost Kraaijeveld <J.Kraaijeveld@Askesis.nl>
Cc: Pgsql-sql@postgresql.org <Pgsql-sql@postgresql.org>
Subject: Re: How to get a count() where column < ''?
Date: Sun, 4 Dec 2005 13:33:56 -0800 (PST)
Message-ID: <20051204133233.O57404@megazone.bigpanda.com> (raw)
In-Reply-To: <1133730772.5560.8.camel@Panoramix>
References: <1133730772.5560.8.camel@Panoramix>
On Sun, 4 Dec 2005, Joost Kraaijeveld wrote:
> Hi,
>
> I want the number of customers that have a zipCode smaller tha a given
> value. The foolowing query doe snot work : I get an error (ERROR:
> column "addresses.zipcode" must appear in the GROUP BY clause or be used
> in an aggregate function) and I do not know how to solve it.
>
> SELECT COUNT(customers.objectid) FROM prototype.customers,
> prototype.addresses
> WHERE
> customers.contactaddress = addresses.objectid
> AND
> zipCode < '2716BN'
> ORDER By zipCode, houseNumber
>
> Anyone an idea?
In a non-grouped query like the above, I don't think that the order by is
meaningful. You only get one row back anyway without a group by, and
there's no single zipCode or houseNumber to associate with the row.
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To: pgsql-sql@postgresql.org
Cc: sszabo@megazone.bigpanda.com, J.Kraaijeveld@Askesis.nl
Subject: Re: How to get a count() where column < ''?
In-Reply-To: <20051204133233.O57404@megazone.bigpanda.com>
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