From: Aarni Ruuhimäki <aarni@kymi.com>
To: pgsql-sql@postgresql.org
Subject: Re: interval as hours or minutes ?
Date: Thu, 8 Feb 2007 13:17:57 +0200
Message-ID: <200702081317.57255.aarni@kymi.com> (raw)
In-Reply-To: <45CB041D.A3DD.0030.0@indicator.be>
References: <200702071903.35126.aarni@kymi.com>
<200702081201.18645.aarni@kymi.com>
<45CB041D.A3DD.0030.0@indicator.be>
Ahh,
Forgot about trunc() in the midst of all this ...
Thank you guys again !
Aarni
On Thursday 08 February 2007 12:06, Bart Degryse wrote:
> Use trunc instead of round.
> Also take a look at ceil and floor functions
>
> >>> Aarni Ruuhimäki <aarni@kymi.com> 2007-02-08 11:01 >>>
>
> On Thursday 08 February 2007 00:09, you wrote:
> > select extract(epoch from (timestamp '2007-02-07 16:24:00' -
>
> timestamp
>
> > '2007-02-05 13:00:01'))/60 as minutes;
> >
> > minutes
> > ------------------
> > 3083.98333333333
> > (1 row)
> >
> > select round(extract(epoch from (timestamp '2007-02-07 16:24:00' -
> > timestamp '2007-02-05 13:00:01'))/60) as minutes;
> >
> > minutes
> > ---------
> > 3084
> > (1 row)
>
> Hi Guys,
>
> Charming !
>
> Furher still, I would only want full minutes.
>
> select extract(epoch from (SELECT SUM(stop_date_time - start_date_time)
> FROM
> work_times WHERE user_id = 10 AND start_date_time >= '2007-01-01' AND
> stop_date_time <= '2007-02-28')/60) as mins;
> mins
> -------------
> 3728.733333
> (1 row)
>
> select convert_interval((SELECT SUM(stop_date_time - start_date_time)
> FROM
> work_times WHERE user_id = 10 AND start_date_time >= '2007-01-01' AND
> stop_date_time <= '2007-02-28'),'minutes') as minutes;
> minutes
> --------------------------
> 3728.73333333333 minutes
> (1 row)
>
> select round(extract(epoch from (SELECT SUM(stop_date_time -
> start_date_time)
> FROM work_times WHERE user_id = 10))/60) as mins;
> mins
> ------
> 3729
> (1 row)
>
> So instead of rounding up to 3729 the result would have to be
> 'stripped' to
> 3728 ?
>
> Thanks,
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Subject: Re: interval as hours or minutes ?
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