From: David Flegl <ml_flegl@centrum.cz>
To: pgsql-sql@postgresql.org
Subject: Re: hi
Date: Tue, 24 Apr 2007 15:06:42 +0200
Message-ID: <200704241506.20350@centrum.cz> (raw)
In-Reply-To: <A70AE049E81A6A40879D5DC0AC8C38C908CD9133@venus.infics.com>
References: <A70AE049E81A6A40879D5DC0AC8C38C908CD9133@venus.infics.com>
Hi,
try this. It's working...
SELECT t1.sno, sum(t2.value)
FROM temp as t1, temp as t2
WHERE t1.sno >= t2.sno
GROUP BY t1.sno;
but not completely. The problem is the this suppose your sno is uniqu. But as I see 3 is not.
Anyway it may help you.
>I have the data like this in temp table
>
>SQL> Select sno, value from temp;
>
>SNO Value
>
>1 650.00
>
>2 850.00
>
>3 640.00
>
>3 985.00
>
>5 987.00
>
>9 9864.00
>
>7 875.00
>
>Now, I want display the result like this...
>
>SQL> Select sno, value, get_sum(value) as sum from temp;
>
> SNO Value SUM
>
>1 650.00 650.00
>
>2 850.00 1500.00 --650+850
>
>3 640.00 2140.00 --1500+640
>
>3 985.00 3125.00 -- 2140+985
>
>5 987.00 4112.00
>
>9 9864.00 13976.00
>
>7 875.00 14851.00
>
>
>
>Any one can tell me query for this .. I don't want any procedure or
>function...
>
>
>
>
>
>Thanks & Regards
>
>Penchal Reddy
>
>
>
>
>
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To: pgsql-sql@postgresql.org
Cc: ml_flegl@centrum.cz
Subject: Re: hi
In-Reply-To: <200704241506.20350@centrum.cz>
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