From: Bryan Emrys <bryan.emrys@gmail.com>
To: Rodrigo E. De León Plicet <rdeleonp@gmail.com>
Cc: pgsql-sql@postgresql.org
Subject: Re: SQL dealing with subquery
Date: Wed, 16 Jan 2008 07:54:41 -0800
Message-ID: <200801160754.41769.bryan.emrys@gmail.com> (raw)
In-Reply-To: <a55915760801151240w61aa3520g548eff734190061e@mail.gmail.com>
References: <eee4647d0801151004t288b0819ocbc0cae8e0df7f24@mail.gmail.com>
<a55915760801151240w61aa3520g548eff734190061e@mail.gmail.com>
Thanks. It throws off a few extra countries where there is only one treaty, but those are
few enough that I can handle them manually.
I thought the solution was also going to give me insight into how to select just the lowest
rate from each couple, (i.e. for each payor, who is the lowest rate payee) but it looks like
I'll have find some time to think about that later (I've also got to think about what to do in tie situations.).
Again, thanks.
Bryan
On Tuesday 15 January 2008 12:40:13 pm Rodrigo E. De León Plicet wrote:
> On Jan 15, 2008 1:04 PM, Bryan Emrys <bryan.emrys@gmail.com> wrote:
> > In other words, in the sample above, I only want to return:
> > 'Canada','Ireland',0
> > 'Canada','Netherlands',5
>
> Try (untested):
>
> SELECT t2.*
> FROM (SELECT payor
> FROM treaty_rates
> WHERE payee IN ('Netherlands', 'Ireland')
> GROUP BY payor
> HAVING MIN (rate) != MAX (rate)) t1
> JOIN
> treaty_rates t2 ON t1.payor = t2.payor
> WHERE t2.payee IN ('Netherlands', 'Ireland');
>
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To: pgsql-sql@postgresql.org
Cc: bryan.emrys@gmail.com, rdeleonp@gmail.com
Subject: Re: SQL dealing with subquery
In-Reply-To: <200801160754.41769.bryan.emrys@gmail.com>
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