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From: Achilleas Mantzios <achill@matrix.gatewaynet.com>
To: pgsql-sql@postgresql.org
Subject: Re: join with an array
Date: Wed, 24 Feb 2010 16:39:00 +0200
Message-ID: <201002241639.00331.achill@matrix.gatewaynet.com> (raw)
In-Reply-To: <20100224133447.GA18435@apartia.fr>
References: <20100224124023.GA16500@apartia.fr>
	<20100224130909.GL22249@a-kretschmer.de>
	<20100224133447.GA18435@apartia.fr>

Στις Wednesday 24 February 2010 15:34:48 ο/η Louis-David Mitterrand έγραψε:

> Here is a test case I built. I want to list all cruises by cruise_type
> but after merging cruise_type that have the same cruise_type_name:
> 
> drop table cruise;
> drop table cruise_type;
> 
> create table cruise_type (
>     id_cruise_type serial primary key,
>     cruise_type_name text
> );
> 
> create table cruise (
>     id_cruise serial,
>     id_cruise_type integer references cruise_type,
>     cruise_date timestamp default now()
> );
> 
> insert into cruise_type (cruise_type_name) values 
> ('5 day eastern carribean cruise'),
> ('5 day western carribean cruise'),
> ('5 day eastern carribean cruise'),
> ('5 day western carribean cruise')
> ;
> 
> insert into cruise (id_cruise_type) values 
> (1),
> (2),
> (3),
> (4),
> (1),
> (2),
> (3),
> (4)
> ;
> 
> select array_agg(ct.id_cruise_type),ct.cruise_type_name from cruise_type ct join cruise c on (c.id_cruise = any(array_agg)) group by cruise_type_name;
> 

You dont specify (in english) what you exactly want to achive, but here is my shot:
1st, get the cruises by cruise type:
select ct.id_cruise_type,array_agg(c.id_cruise) as "List of Cruises" from cruise_type ct, cruise c WHERE c.id_cruise_type=ct.id_cruise_type GROUP BY ct.id_cruise_type ORDER BY ct.id_cruise_type;
 id_cruise_type | List of Cruises
----------------+-----------------
              1 | {1,5}
              2 | {2,6}
              3 | {3,7}
              4 | {4,8}
(4 rows)

test=#   
Then you may pretify this to include the name of each cruise type as well:

select ct.id_cruise_type,ct.cruise_type_name,array_agg(c.id_cruise) as "List of Cruises" from cruise_type ct, cruise c WHERE c.id_cruise_type=ct.id_cruise_type GROUP BY ct.id_cruise_type,ct.cruise_type_name ORDER BY ct.id_cruise_type;
 id_cruise_type |        cruise_type_name        | List of Cruises
----------------+--------------------------------+-----------------
              1 | 5 day eastern carribean cruise | {1,5}
              2 | 5 day western carribean cruise | {2,6}
              3 | 5 day eastern carribean cruise | {3,7}
              4 | 5 day western carribean cruise | {4,8}
(4 rows)

EXERCISE:
Why cant we exclude ct.id_cruise_type from the select clause and group by of the above query?

-- 
Achilleas Mantzios



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