From: A. Kretschmer <andreas.kretschmer@schollglas.com>
To: pgsql-sql@postgresql.org
Subject: Re: sum an alias
Date: Fri, 4 Jun 2010 07:54:34 +0200
Message-ID: <20100604055434.GA19411@a-kretschmer.de> (raw)
In-Reply-To: <AANLkTil0i1cg1DulN4sIEIa08qM5VU5VuLoKB7u8g1-D@mail.gmail.com>
References: <AANLkTil0i1cg1DulN4sIEIa08qM5VU5VuLoKB7u8g1-D@mail.gmail.com>
In response to Wes James :
> In the statement:
>
> select
> MAX(page_count_count) - MIN(page_count_count) as day_tot,
> MAX(page_count_count) as day_max, sum(MAX(page_count_count) -
> MIN(page_count_count)) as tot,
> page_count_pdate
> from page_count
> group by page_count_pdate order by page_count_pdate
>
> Is there a way to do sum(day_tot) also in the same statement?
Is this the correct table-definition?
test=# \d page_count
Table "public.page_count"
Column | Type | Modifiers
------------------+---------+-----------
page_count_pdate | date |
page_count_count | integer |
If yes, your SQL is wrong:
test=# select
MAX(page_count_count) - MIN(page_count_count) as day_tot,
MAX(page_count_count) as day_max, sum(MAX(page_count_count) -
MIN(page_count_count)) as tot,
page_count_pdate
from page_count
group by page_count_pdate order by page_count_pdate;
ERROR: aggregate function calls cannot be nested
LINE 3: MAX(page_count_count) as day_max, sum(MAX(page_count_cou...
Can you provide the correct table definition?
Regards, Andreas
--
Andreas Kretschmer
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To: pgsql-sql@postgresql.org
Cc: andreas.kretschmer@schollglas.com
Subject: Re: sum an alias
In-Reply-To: <20100604055434.GA19411@a-kretschmer.de>
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