From: Tom Lane <tgl@sss.pgh.pa.us>
To: MHahn@seeandswim.com
Cc: pgsql-sql@postgresql.org
Subject: Re: All columns from table in a joined query
Date: Wed, 23 Aug 2006 17:26:57 -0400
Message-ID: <24653.1156368417@sss.pgh.pa.us> (raw)
In-Reply-To: <14106936.1156360501724.JavaMail.teamon@b217.teamon.com>
References: <14106936.1156360501724.JavaMail.teamon@b217.teamon.com>
MHahn@seeandswim.com writes:
> I've been trying to figure out how to do the following:
> Select schedule.* from schedule join meetingday on schedule.id = meetingday.scheduleid where sessionnumber = 165 group by schedule.* order by min(meetingday.date);
I think what you're after is
select * from schedule where sessionnumber = 165
order by (select min(meetingday.date) from meetingday
where schedule.id = meetingday.scheduleid);
regards, tom lane
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To: pgsql-sql@postgresql.org
Cc: tgl@sss.pgh.pa.us, MHahn@seeandswim.com
Subject: Re: All columns from table in a joined query
In-Reply-To: <24653.1156368417@sss.pgh.pa.us>
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