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* All columns from table in a joined query
@ 2006-08-23 19:14 MHahn@seeandswim.com
2006-08-23 19:44 ` Re: All columns from table in a joined query Sumeet <asumeet@gmail.com>
2006-08-23 21:26 ` Re: All columns from table in a joined query Tom Lane <tgl@sss.pgh.pa.us>
0 siblings, 2 replies; 3+ messages in thread
From: MHahn@seeandswim.com @ 2006-08-23 19:14 UTC (permalink / raw)
To: pgsql-sql
I've been trying to figure out how to do the following:
Select schedule.* from schedule join meetingday on schedule.id = meetingday.scheduleid where sessionnumber = 165 group by schedule.* order by min(meetingday.date);
Is this possible in any way, or do I need to list each field of the schedule table to get all of them?
^ permalink raw reply [nested|flat] 3+ messages in thread
* Re: All columns from table in a joined query
2006-08-23 19:14 All columns from table in a joined query MHahn@seeandswim.com
@ 2006-08-23 19:44 ` Sumeet <asumeet@gmail.com>
1 sibling, 0 replies; 3+ messages in thread
From: Sumeet @ 2006-08-23 19:44 UTC (permalink / raw)
To: MHahn@seeandswim.com <MHahn@seeandswim.com>; +Cc: pgsql-sql
You need to create a custom aggregate for this
CREATE AGGREGATE array_accum (
sfunc = array_append,
basetype = anyelement,
stype = anyarray,
initcond = '{}'
);
then use the field names in your query like this
select array_to_string(array_accum(field1 || '@' || field2),'#') as
field_alias from table_name
records will be seperated by '#'
hope this helps.
On 8/23/06, MHahn@seeandswim.com <MHahn@seeandswim.com> wrote:
>
> I've been trying to figure out how to do the following:
>
> Select schedule.* from schedule join meetingday on schedule.id =
> meetingday.scheduleid where sessionnumber = 165 group by schedule.* order
> by min(meetingday.date);
>
> Is this possible in any way, or do I need to list each field of the
> schedule table to get all of them?
>
> ---------------------------(end of broadcast)---------------------------
> TIP 5: don't forget to increase your free space map settings
>
--
Thanks,
Sumeet Ambre
Masters of Information Science Candidate,
Indiana University.
On 8/23/06, MHahn@seeandswim.com <MHahn@seeandswim.com> wrote:
>
> I've been trying to figure out how to do the following:
>
> Select schedule.* from schedule join meetingday on schedule.id =
> meetingday.scheduleid where sessionnumber = 165 group by schedule.* order
> by min(meetingday.date);
>
> Is this possible in any way, or do I need to list each field of the
> schedule table to get all of them?
>
> ---------------------------(end of broadcast)---------------------------
> TIP 5: don't forget to increase your free space map settings
>
--
Thanks,
Sumeet Ambre
Masters of Information Science Candidate,
Indiana University.
^ permalink raw reply [nested|flat] 3+ messages in thread
* Re: All columns from table in a joined query
2006-08-23 19:14 All columns from table in a joined query MHahn@seeandswim.com
@ 2006-08-23 21:26 ` Tom Lane <tgl@sss.pgh.pa.us>
1 sibling, 0 replies; 3+ messages in thread
From: Tom Lane @ 2006-08-23 21:26 UTC (permalink / raw)
To: MHahn@seeandswim.com; +Cc: pgsql-sql
MHahn@seeandswim.com writes:
> I've been trying to figure out how to do the following:
> Select schedule.* from schedule join meetingday on schedule.id = meetingday.scheduleid where sessionnumber = 165 group by schedule.* order by min(meetingday.date);
I think what you're after is
select * from schedule where sessionnumber = 165
order by (select min(meetingday.date) from meetingday
where schedule.id = meetingday.scheduleid);
regards, tom lane
^ permalink raw reply [nested|flat] 3+ messages in thread
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2006-08-23 19:14 All columns from table in a joined query MHahn@seeandswim.com
2006-08-23 19:44 ` Sumeet <asumeet@gmail.com>
2006-08-23 21:26 ` Tom Lane <tgl@sss.pgh.pa.us>
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