From: Rudi Starcevic <rudi@oasis.net.au>
To: pgsql-sql@postgresql.org
Subject: Re: Count equals 0
Date: Thu, 20 Mar 2003 15:38:48 +1000
Message-ID: <3E7953E8.9090800@oasis.net.au> (raw)
References: <ea0824a43c82b86591e6b913514cf5ba@biglumber.com>
Hi,
Thank you kindly for your suggetions.
Greg's suggestion was closest to what I needed ( spot on in fact )
Cheers
Rudi.
greg@turnstep.com wrote:
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>>I've tries Left outer join's with and without coalesce without joy so far.
>>Please check out my query.
>>
>>
>
>Your query is good, let's just make the whole thing a subselect
>and use an outer join to get the missing sites:
>
>SELECT u2.site_name, COALESCE(u1.total, 0)
>FROM
>(
> SELECT site_name, COUNT(cus_id) AS total
> FROM user_main um
> WHERE NOT EXISTS
> (
> SELECT cus_id
> FROM user_sys_messages usm
> WHERE usm.cus_id = um.cus_id
> )
> GROUP BY site_name
>) AS u1
>RIGHT OUTER JOIN user_main u2 USING (site_name)
>GROUP BY 1,2
>ORDER BY u2.site_name;
>
>
>You could also write this as a LEFT OUTER JOIN (by putting the subselect second),
>but I think it is clearer if the USING or ON is as close as possible to the
>JOIN statement.
>
>
>- --
>Greg Sabino Mullane greg@turnstep.com
>PGP Key: 0x14964AC8 200303181009
>
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To: pgsql-sql@postgresql.org
Cc: rudi@oasis.net.au
Subject: Re: Count equals 0
In-Reply-To: <3E7953E8.9090800@oasis.net.au>
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