From: Guy Fraser <guy@incentre.net>
To: pgsql-sql@postgresql.org
Subject: Re: Calculating with the time
Date: Fri, 30 May 2003 15:13:35 -0600
Message-ID: <3ED7C97F.7020805@incentre.net> (raw)
References: <Law12-F35awhftgLeCR0002781b@hotmail.com>
Is this what you are looking for?
test=# select 'now'::time as test,'2003-05-30 14:51:38-06'::timestamptz
as stamp into temp cruft;
SELECT
test=# select test,stamp,test - stamp::time as diff from cruft;
test | stamp | diff
-----------------+------------------------+-----------------
15:09:28.862728 | 2003-05-30 14:51:38-06 | 00:17:50.862728
(1 row)
test=# select test,stamp,reltime(test - stamp::time) as diff from cruft;
test | stamp | diff
-----------------+------------------------+----------
15:09:28.862728 | 2003-05-30 14:51:38-06 | 00:17:50
(1 row)
test=# drop table cruft;
DROP TABLE
Guy
Katka a Daniel Dunajsky wrote:
> Hello All,
>
> I am looking for an advice how to do calculation with the time. I do
> have a column with datatype 'timestamp with time zone'. The value is
> '2003-03-22 07:53:56-07' for instance. I would like to select it from
> the table with result of '07:59:59' – '07:53:56', so the query should
> return '00:06:03'.
>
> Thank you for your time.
>
> DanielD
>
Reply instructions:
You may reply publicly to this message via plain-text email
using any one of the following methods:
* Reply to all the recipients using the --to and --cc options:
reply via email
To: pgsql-sql@postgresql.org
Cc: guy@incentre.net
Subject: Re: Calculating with the time
In-Reply-To: <3ED7C97F.7020805@incentre.net>
* Save the following mbox file, import it into your mail client,
and reply-to-all from there: mbox
This inbox is served by DDX for PostgreSQL; see mirroring instructions
for how to clone and mirror all data and code used for this inbox