From: Richard Huxton <dev@archonet.com>
To: Her Goo <gu_he@msn.com>
Cc: pgsql-sql@postgresql.org
Subject: Re: sql: "LIKE" problem
Date: Mon, 14 Mar 2005 08:16:07 +0000
Message-ID: <42354847.9070403@archonet.com> (raw)
In-Reply-To: <BAY11-DAV4899E308FCFAA7E626003F85560@phx.gbl>
References: <BAY11-DAV4899E308FCFAA7E626003F85560@phx.gbl>
Her Goo wrote:
> I am using "postgresql-7.3.2-1" now!
>
> I met a problem when using "LIKE" in "WHERE" clause.
> For example, a table named "t_test", and its data looks like below:
>
> # SELECT * FROM t_test;
> id | c_name
> ----+--------
> 1 | abc\
> 2 | abc\de
> (2 rows)
> # SELECT * FROM t_test WHERE c_name LIKE 'abc\d%';
> id | c_name
> ----+--------
> (0 rows)
>
> I don't know why the result is "0 rows"(why not is "1 rows"),
> And I have trid "LIKE 'abc\\d%'", the result is also "0 rows".
You'll need to escape the backslash twice. Once for the SQL-level
parsing and once for the LIKE pattern-matching itself.
SELECT * FROM t_test WHERE c_name LIKE 'abc\\\\d%';
--
Richard Huxton
Archonet Ltd
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To: pgsql-sql@postgresql.org
Cc: dev@archonet.com, gu_he@msn.com
Subject: Re: sql: "LIKE" problem
In-Reply-To: <42354847.9070403@archonet.com>
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