From: grupos <grupos@carvalhaes.net>
To: Greg Sabino Mullane <greg@turnstep.com>
Cc: pgsql-sql@postgresql.org
Subject: Re: SELECT with sum on groups ORDERING by the subtotals
Date: Fri, 17 Jun 2005 14:15:30 -0300
Message-ID: <42B30532.1040405@carvalhaes.net> (raw)
In-Reply-To: <271d057bf6acfee775e7c47fe899cc9e@biglumber.com>
References: <271d057bf6acfee775e7c47fe899cc9e@biglumber.com>
Hi Greg,
Thanks for your reply.
Yes, same group of code...
Perfect solution, simple and efficient. Thank you very much!!!
Cheers,
Rodrigo Carvalhaes
Greg Sabino Mullane wrote:
>-----BEGIN PGP SIGNED MESSAGE-----
>Hash: SHA1
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>>I need an subtotal for all the products with the same group and that the
>>query be ordered by the bigger subtotal.
>>
>>
>
>(please proofread: the subtotals in your example output did not add up)
>
>By "same group" I presume you mean the same code, as you don't actually use
>the "group varchar(10)" column you created in your example. A major problem
>you have is that you have no other way of ordering the rows except by the
>code. So having a running subtotal is fairly pointless, as the items within
>each code will appear randomly. Since only the grand total for each code is
>significant, you could write something like this:
>
>SELECT t.*, s.subtotal FROM
> (SELECT code, SUM(total) AS subtotal FROM test GROUP BY 1) s,
> test t
> WHERE s.code = t.code
> ORDER BY subtotal desc;
>
> code | description | quant | price | total | subtotal
>- -------+-------------+-------+-------+-------+----------
> 99120 | PRODUCT C | 10 | 0.8 | 8 | 338
> 99120 | PRODUCT C | 100 | 0.8 | 80 | 338
> 99120 | PRODUCT C | 200 | 0.8 | 160 | 338
> 99120 | PRODUCT C | 100 | 0.9 | 90 | 338
> 92110 | PRODUCT A | 10 | 1 | 10 | 120
> 92110 | PRODUCT A | 5 | 0.9 | 9 | 120
> 92110 | PRODUCT A | 100 | 0.9 | 90 | 120
> 92110 | PRODUCT A | 10 | 1.1 | 11 | 120
> 92190 | PRODUCT b | 10 | 1.1 | 11 | 41
> 92190 | PRODUCT b | 10 | 1.1 | 11 | 41
> 92190 | PRODUCT b | 10 | 1.1 | 11 | 41
> 92190 | PRODUCT b | 20 | 0.8 | 8 | 41
>
>If you don't need all that intermediate stuff:
>
>SELECT code, SUM(total) AS subtotal FROM test GROUP BY 1 ORDER BY 2 DESC;
>
> code | subtotal
>- -------+----------
> 99120 | 338
> 92110 | 120
> 92190 | 41
>
>If you do need the other rows, you will have to specify a way of ordering
>the rows within a code group.
>
>- --
>Greg Sabino Mullane greg@turnstep.com
>PGP Key: 0x14964AC8 200506161458
>http://biglumber.com/x/web?pk=2529DF6AB8F79407E94445B4BC9B906714964AC8
>
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--
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To: pgsql-sql@postgresql.org
Cc: grupos@carvalhaes.net, greg@turnstep.com
Subject: Re: SELECT with sum on groups ORDERING by the subtotals
In-Reply-To: <42B30532.1040405@carvalhaes.net>
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