From: Erik Jones <erik@myemma.com>
To: Gary Stainburn <gary.stainburn@ringways.co.uk>
Cc: pgsql-sql@postgresql.org
Subject: Re: join/group/count query.
Date: Wed, 20 Dec 2006 10:32:00 -0600
Message-ID: <45896580.5090500@myemma.com> (raw)
In-Reply-To: <200612201620.07863.gary.stainburn@ringways.co.uk>
References: <200612201012.25960.gary.stainburn@ringways.co.uk>
<1166612996.6369.282.camel@localhost.localdomain>
<45895AEB.20501@myemma.com>
<200612201620.07863.gary.stainburn@ringways.co.uk>
Gary Stainburn wrote:
>> And, I may be missing something, but I'm having a hard time
>> understanding why you have all of those select columns of the form:
>>
>> count (case when o_model = 5 then 1 else NULL end) as KA,
>>
>> Considering that that can only return 1 or 0, the case statement would do.
>> Is it to avoid putting all of the column names in the group by clause?
>> That's hackish and is as much or more typing.
>>
>> With regards to what you are actually trying to do, giving us your table
>> definitions and what you are trying to achieve would help a lot more than
>> just telling us the problem you are having. The column names in your query
>> are in no way descriptive and tell us nothing about your actual table
>> structure.
>>
>
> The order_details view is a join of the orders table to the other tables.
>
> The order table contains the orders.
>
> Each order has a business partner which is in a separate table. p_id is the
> key, p_name is the name of the partner.
>
> Each order is for a single vehicle, which must be of a specific mode. The
> models are also stored in a separate table. o_model is the attribute in the
> orders table that contains the key to the models table.
>
> The output I'm getting is below, which is what I want. For each partner I get
> a total followed by a breakdown by model the orders for the current month.
>
> key|p_id| p_name | total | ka | focus | c_max | s_max | fiesta |
> fusion | mondeo | galaxy | ranger | connect | transit | fiesta_van
> ---+----+----------------+-------+----+-------+-------+-------+--------+--------+--------+--------+--------+---------+---------+------------
> 40| 40|rrrrrrrrrrrrrrr | 2 |0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 1 |0
> 30| 30|rrrrr Group Plc | 2 |0 | 2 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |0
> 78| 78|rrrrr rrrrrrrrr | 2 |0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 |0
> 46| 46|rrrrrrrrrrrr ) | 3 |0 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 0 |0
> 3| 3|eeeee | 8 |0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 2 | 2 | 4 |0
> 9| 9|eee | 3 |0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 2 |0
> 12| 12|qqqqqqqqqqqq |13 |0 | 0 | 0 | 0 | 0 | 0 | 2 | 0 | 0 | 5 | 6 |0
> 10| 10|rr Motor | 7 |0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 2 | 5 |0
> 34| 34|ffffff fffffff | 3 |0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 2 |0
> 102| 102|xxxxxxxx xxxxxxx| 1 |0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 |0
>
Ok, then, yeah, I read those count statements wrong and the crosstab
contrib is what you're looking for.
--
erik jones <erik@myemma.com>
software development
emma(r)
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To: pgsql-sql@postgresql.org
Cc: erik@myemma.com, gary.stainburn@ringways.co.uk
Subject: Re: join/group/count query.
In-Reply-To: <45896580.5090500@myemma.com>
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