From: Dani Castaños <dcastanos@androme.es>
To: pgsql-sql@postgresql.org
Subject: Re: Results per letter query
Date: Thu, 21 Jun 2007 12:42:52 +0200
Message-ID: <467A562C.2020504@androme.es> (raw)
In-Reply-To: <20070621100425.GH1405@a-kretschmer.de>
References: <467A406A.3060907@androme.es>
<20070621100425.GH1405@a-kretschmer.de>
>> Hi!
>>
>> I'm trying to build a query to get if there is an occurrence for a field
>> for each alphabetical letter.
>> My first thought to know it was to do something like:
>>
>> SELECT COUNT(field) FROM table WHERE UPPER( field ) LIKE UPPER( 'A%' )
>> LIMIT 1;
>> SELECT COUNT(field) FROM table WHERE UPPER( field ) LIKE UPPER( 'B%' )
>> LIMIT 1;
>> SELECT COUNT(field) FROM table WHERE UPPER( field ) LIKE UPPER( 'C%' )
>> LIMIT 1;
>> ...
>> and so on...
>>
>> Is there any way to do it in only one query??
>>
>
> I'm not sure if i understand you correctly, sorry, if not.
>
> test=*# select * from w;
> t
> --------
> test
> foo
> bar
> foobar
> (4 rows)
>
> test=*# select chr(x), count(1) from generate_series(65,90) x, w where
> upper(substring (w.t from 1 for 1)) ~ chr(x) group by 1;
> chr | count
> -----+-------
> T | 1
> B | 1
> F | 2
> (3 rows)
>
>
>
> Andreas
>
It's exactly what i want. Just one more thing... What if i want also the
ones that begin by a non-alphabetical character.
In your example:
test=*# select * from w;
t
--------
test
foo
bar
foobar
1foobar
/ertw
@weras
and have:
chr | count
-----+-------
T | 1
B | 1
F | 2
_ | 3
(4 rows)
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To: pgsql-sql@postgresql.org
Cc: dcastanos@androme.es
Subject: Re: Results per letter query
In-Reply-To: <467A562C.2020504@androme.es>
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