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From: Philippe Lang <philippe.lang@attiksystem.ch>
To: pgsql-sql@postgresql.org
Subject: Re: Table transform query
Date: Tue, 18 Sep 2007 15:49:47 +0200
Message-ID: <6C0CF58A187DA5479245E0830AF84F4218CF20@poweredge.attiksystem.ch> (raw)
References: <6C0CF58A187DA5479245E0830AF84F4218CF1F@poweredge.attiksystem.ch>

pgsql-sql-owner@postgresql.org wrote:

> Hi,
> 
> I'm trying to find out how to transform this kind of table data
> (history of rental data in a firm): 

...     

I have answred my own question: yes, there is a pure SQL solution, with
a subselect:

CREATE TABLE foo (
    serial integer,
    delivery character(1),
    date integer
);

INSERT INTO foo (serial, delivery, date) VALUES (1, 'L', 1);
INSERT INTO foo (serial, delivery, date) VALUES (2, 'L', 1);
INSERT INTO foo (serial, delivery, date) VALUES (3, 'L', 1);
INSERT INTO foo (serial, delivery, date) VALUES (1, 'R', 2);
INSERT INTO foo (serial, delivery, date) VALUES (2, 'R', 2);
INSERT INTO foo (serial, delivery, date) VALUES (4, 'L', 2);
INSERT INTO foo (serial, delivery, date) VALUES (5, 'L', 3);
INSERT INTO foo (serial, delivery, date) VALUES (3, 'R', 3);
INSERT INTO foo (serial, delivery, date) VALUES (4, 'R', 3);
INSERT INTO foo (serial, delivery, date) VALUES (1, 'L', 4);


-------------
select 

f.serial, 
f.date as dateL,
( select f2.date from foo as f2 
  where f2.serial = f.serial 
  and f2.date > f.date 
  and f2.delivery = 'R' 
  order by f2.date asc 
  limit 1
) as dateR

from foo as f
where f.delivery = 'L'
order by f.serial, f.date
-------------


I'm not sure if we could use a self-join here...


Cheers,


Philippe Lang



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