From: Professor Flávio Brito <prof.flaviobrito@gmail.com>
To: Colin Wetherbee <cww@denterprises.org>
Cc: pgsql-sql@postgresql.org
Subject: Re: Function returns error (view)
Date: Tue, 26 Feb 2008 13:48:14 -0300
Message-ID: <6a5e3a6f0802260848u5c780346m45059969439c9627@mail.gmail.com> (raw)
In-Reply-To: <47C44023.4080007@denterprises.org>
References: <6a5e3a6f0802260832k9c1375ap632f8adad0740fa2@mail.gmail.com>
<47C44023.4080007@denterprises.org>
<www.cecierj.rj.gov.br>
Hi Colin
When I translated from Portuguese to English I forgot a letter, but using
the corrected name I received an error.
2008/2/26, Colin Wetherbee <cww@denterprises.org>:
>
> Professor Flávio Brito wrote:
> > When I Test my view I receive
> >
> > SELECT seach_password('user_login_foo')
>
> [...]
>
> > ERROR: column "user_login_foo" does not exist
> > SQL state: 42703
> > Context: PL/pgSQL function "search_password" line 14 at for over execute
> > statement
>
>
> seach_password and
> search_password are different.
>
> Perhaps you have two functions with similar names, and one is broken?
>
>
> Colin
>
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Subject: Re: Function returns error (view)
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