From: Professor Flávio Brito <prof.flaviobrito@gmail.com>
Cc: pgsql-sql@postgresql.org
Subject: Re: Function returns error (view)
Date: Tue, 26 Feb 2008 15:20:39 -0300
Message-ID: <6a5e3a6f0802261020o51327bceof4845c47ae1b099d@mail.gmail.com> (raw)
In-Reply-To: <47C4539D.A3DD.0030.0@indicator.be>
References: <6a5e3a6f0802260832k9c1375ap632f8adad0740fa2@mail.gmail.com>
<47C4539D.A3DD.0030.0@indicator.be>
Hi
After I did it I received it
ERROR: set-valued function called in context that cannot accept a set
SQL state: 0A000
Context: PL/pgSQL function "seach_password(" line 14 at return next
Error at WHERE login= USER_FOO ??
Thanks for your help
Flávio
2008/2/26, Bart Degryse <Bart.Degryse@indicator.be>:
>
> I think you have a quoting problem
> You want something like
> WHERE login= 'Flavo'
> But you're making something like
> WHERE login = Flavo
>
> Something like this should work...
> CREATE OR REPLACE FUNCTION seach_password(USER_FOO
> IN table_user.login%TYPE)
> RETURNS SETOF vw_change_password AS
> $BODY$
> DECLARE
> r vw_change_password%ROWTYPE;
> USER_FOO alias for $1;
> BEGIN
> FOR r IN (
> SELECT u.cod_user, u.user_name, u.openpsw, t.user_password, t.end,
> t.validate, t.date_add, t.user_time, u.ok
> FROM usuario u, change_user_password t
> WHERE u.cod_user = t.cod_user AND t.cod_user IN (SELECT cod_user FROM
> table_user WHERE login= USER_FOO))
> LOOP
> RETURN NEXT r;
> END LOOP;
> IF NOT FOUND THEN
> RAISE EXCEPTION 'USER not found (%)', USER_FOO;
> END IF;
> RETURN;
> END
> $BODY$
> LANGUAGE 'plpgsql' VOLATILE;
>
>
> >>> "Professor Flávio Brito" <prof.flaviobrito@gmail.com> 2008-02-26 17:32
> >>>
> Hi
>
> Don't know why I can't receive a return like my view fields (I'm newbie in
> plpgsql). Postgresql returns me a erro . How can I received a answer like my
> view structure?
>
> When I Test my view I receive
>
> SELECT seach_password('user_login_foo')
>
> My view returns me
>
> 25746;"MARCELO
> ";"bio1";"bio1";"2008-02-19";"FALSE";"2008-02-12";"2008-02-12 12:51:
> 40.229282";"TRUE"
> 30356;"JOSE DE JESUS
> ";"977";"377";"2008-02-19";"FALSE";"2008-02-12";"2008-02-12 12:52:
> 19.688381";"TRUE"
>
> It's OK
>
> but when I use function it returns me
>
> ERROR: column "user_login_foo" does not exist
> SQL state: 42703
> Context: PL/pgSQL function "search_password" line 14 at for over execute
> statement
>
> Where is my fault?
>
> Thanks
>
> Flávio
>
>
> *************************************************************************************************************
> vw_change_password attributes
>
> cod_user integer,
> user_name varchar(150),
> openpsw varchar (32),
> user_password varchar (50),
> end timestamp,
> validate boolean,
> date_add timestamp,
> user_time timestamp,
> ok boolean
>
>
> CREATE OR REPLACE FUNCTION seach_password(USER_FOO varchar(100))
> RETURNS SETOF vw_change_password AS
> $BODY$
> DECLARE
> r vw_change_password%ROWTYPE;
> USER_FOO alias for $1;
> sql TEXT;
> BEGIN
> sql= 'SELECT u.cod_user, u.user_name, u.openpsw, t.user_password, t.end,
> t.validate, t.date_add, t.user_time, u.ok
> FROM usuario u, change_user_password t
> WHERE u.cod_user = t.cod_user AND t.cod_user
> IN
> (SELECT cod_user
> FROM table_user
> WHERE login='||USER_FOO||')';
>
> FOR r IN EXECUTE sql
> LOOP
> RETURN NEXT r;
> END LOOP;
> IF NOT FOUND THEN
> RAISE EXCEPTION 'USER not found', USER_FOO;
> END IF;
> RETURN;
> END
> $BODY$
> LANGUAGE 'plpgsql' VOLATILE;
>
>
>
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Subject: Re: Function returns error (view)
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