From: Michael J Davis <michael.j.davis@tvguide.com>
To: 'pgsql-sql@postgreSQL.org' <pgsql-sql@postgreSQL.org>
Subject: FW: [SQL] OUTER JOINS
Date: Mon, 19 Apr 1999 21:10:14 -0500
Message-ID: <93C04F1F5173D211A27900105AA8FCFC1453DB@lambic.prevuenet.com> (raw)
*= and =* are Oracle syntax for outer joins.
-----Original Message-----
From: Dan Janowski [SMTP:danj@3skel.com]
<mailto:[SMTP:danj@3skel.com]>
Sent: Monday, April 19, 1999 7:27 AM
To: J_Shevland@TurnAround.com.au
<mailto:J_Shevland@TurnAround.com.au>
Cc: pgsql-sql@postgreSQL.org <mailto:pgsql-sql@postgreSQL.org>
Subject: Re: [SQL] OUTER JOINS
Thanks for giving it a stab. Looking at the available
operators,
there is no =* or *= ops available. Although I am curious
where it
comes from.
Dan
Joe Shevland wrote:
> ...
> select t1.value from table_one t1, table_two t2 where t1.key =
t2.key;
>
> So this would be a straight LEFT join in my understanding. Now,
I'm
> venturing beyond my experience with PostgreSQL here, but you may
be able
> to use the associated SQL syntaxes:
>
> select ... where t1.key *= t2.key
> select ... where t1.key =* t2.key
> ...
>
> Dan Janowski wrote:
> >
> > I've looked through the docs and mail lists but I am coming
> > up short on references for LEFT/RIGHT/FULL OUTER JOIN
> > avalability
> > or functional workarounds. It seems that PostgreSQL does
> > not have it.
> >
> > Any recommendations on how to aproximate the functionality?
> >
> > As a curiosity, is there a problem with supporting these
> > OUTER joins or is it merely on the list?
> >
--
Dan Janowski danj@3skel.com <mailto:danj@3skel.com>
Triskelion Systems,
Inc. Bronx, NY
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To: pgsql-sql@postgresql.org
Cc: michael.j.davis@tvguide.com
Subject: Re: FW: [SQL] OUTER JOINS
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