From: Oliveiros d'Azevedo Cristina <oliveiros.cristina@marktest.pt>
To: Michele Petrazzo - Unipex <michele.petrazzo@unipex.it>
Cc: pgsql-sql@postgresql.org
Subject: Re: group by hour + distinct
Date: Fri, 26 Nov 2010 13:15:14 -0000
Message-ID: <D352FB1B6AD34FC1A0E5052DB2A786A5@marktestcr.marktest.pt> (raw)
References: <4CEF9C66.30100@unipex.it>
<FC442338870D492A930770CD23660616@marktestcr.marktest.pt>
<4CEFAB4F.6000109@unipex.it>
>
> Ciao
>
* Olá!
>> for each hour it will count the number of distinct user_id's there
>> are . If I understood correctly what you need...
>>
>> Can you please test it and see if it is OK for your needs? With me,
>> it worked on the sample data you provided
>>
>
> Yes! Simply perfect!
>
* Great to hear it worked !
>>
>
> Thanks,
> Michele
* Don't mention it ;-)
>
> P.s. Have you some references about the "subquery" keyword? I found only
> the word subquery as "use" (for example: select a from b where id in
> (select id from table)), but not as sql command.
>
>
* I don't know subquery as an SQL keyword too. In the query I gave you the
"subquery" thing was just an alias. Such kind of things are mandatory. If I
try to omit it, I get this error
ERROR: subquery in FROM must have an alias
HINT: For example, FROM (SELECT ...) [AS] foo.
********** Erro **********
ERROR: subquery in FROM must have an alias
Estado de SQL:42601
Sugestão:For example, FROM (SELECT ...) [AS] foo.
So, even though the "subquery" alias was not used anywhere else, I believe
it had to be there, otherwise the SQL parser would complain
Best,
Oliver
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To: pgsql-sql@postgresql.org
Cc: oliveiros.cristina@marktest.pt, michele.petrazzo@unipex.it
Subject: Re: group by hour + distinct
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