From: James Bond <coolofall@hotmail.com>
To: pgsql-sql@postgresql.org
Subject: postgres sql help
Date: Fri, 14 Oct 2011 10:41:46 -0500
Message-ID: <SNT102-W49402A41C6B6599F082D35A8E10@phx.gbl> (raw)
hi, i am fairly new in postgresql, so if anyone can help me would be great
if i simply do:
select ver_no
from version
order by ver_no
the result will be something like this:
.1.3.1
.1.3.2.5.
.1.4.1.7.12
.1.4.11.14.7.
.1.4.3.109.1.
.1.4.8.66.
so as you can see first 3 lines are ok, but how to make 1.4.3.109 come
before 1.4.11 because the third level "3" is smaller than "11". i
understand they are stored as char so i used split_part function to
separate each numbers between "." in a separate column. but when i try
to convert those column into integer, i am getting an error msg saying:
ERROR: invalid input syntax for type numeric: " "
here is my code:
select ver_no, duedate, status,
to_number(split_part(ver_no, '.', 2), '9999') a,
to_number(split_part(ver_no, '.', 3), '9999') b,
to_number(split_part(ver_no, '.', 4), '9999') c,
to_number(split_part(ver_no, '.', 5), '9999') d
from version
order by a,b,c,d
I am not sure if i am heading towards wrong direction but can someone please suggest or give me some other ideas to sort this.
PS: i found some good solution in SQL Server but those commands are not used in postgreSQL.
Thanks in advance
- James
=
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Subject: Re: postgres sql help
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