From: Rodrigo De Leon <rdeleonp@gmail.com>
To: pgsql-sql@postgresql.org
Subject: Re: SELECT substring with regex
Date: Fri, 7 Jul 2006 13:37:08 -0500
Message-ID: <a55915760607071137q2c70346cp5b30cac14beaf1e7@mail.gmail.com> (raw)
In-Reply-To: <44AE9B4F.1020401@numerixtechnology.de>
References: <44AE66E0.1040606@numerixtechnology.de>
<200607071659.14940.gary.stainburn@ringways.co.uk>
<44AE9B4F.1020401@numerixtechnology.de>
On 7/7/06, T E Schmitz <mailreg@numerixtechnology.de> wrote:
> But that takes me to the next problem:
>
> For the sake of the example I simplified the regular pattern.
> In reality, BASE_NAME might be:
>
> 28mm
> 28-70mm
>
> So the reg. expr. requires brackets:
>
> substring (NAME, '^(\\d+(-\\d+)?mm)' ) as BASE_NAME
>
> Actually, the pattern is more complex than that and I cannot see how I
> can express it without brackets.
Maybe:
select
substring ('150mm LD AD Asp XR Macro', '^[\\d-]*mm' ) as BASE_NAME
, substring('150mm LD AD Asp XR Macro','^[\\d-]*mm (.*)$') as SUFFIX;
select
substring ('28-70mm LD AD Asp XR Macro', '^[\\d-]*mm' ) as BASE_NAME
, substring('28-70mm LD AD Asp XR Macro','^[\\d-]*mm (.*)$') as SUFFIX;
etc...
Regards,
Rodrigo
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To: pgsql-sql@postgresql.org
Cc: rdeleonp@gmail.com
Subject: Re: SELECT substring with regex
In-Reply-To: <a55915760607071137q2c70346cp5b30cac14beaf1e7@mail.gmail.com>
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