From: Rodrigo De León <rdeleonp@gmail.com>
To: Bryce Nesbitt <bryce1@obviously.com>
Cc: pgsql-sql@postgresql.org
Subject: Re: Getting pk of the most recent row, in a group by
Date: Mon, 13 Aug 2007 15:16:49 -0500
Message-ID: <a55915760708131316t4ae9e506i3980e4ad87a8268c@mail.gmail.com> (raw)
In-Reply-To: <46C0B994.6090906@obviously.com>
References: <46C0B994.6090906@obviously.com>
On 8/13/07, Bryce Nesbitt <bryce1@obviously.com> wrote:
> In the second example, is it possible to get the primary key of the row
> with the minimum expires time?
SELECT TYPE, MIN(expires), COUNT(*)
, (SELECT MIN(coupon_id)
FROM coupon
WHERE expires = MIN(c.expires)) AS coupon_id
FROM coupon c
GROUP BY TYPE;
Reply instructions:
You may reply publicly to this message via plain-text email
using any one of the following methods:
* Reply to all the recipients using the --to and --cc options:
reply via email
To: pgsql-sql@postgresql.org
Cc: rdeleonp@gmail.com, bryce1@obviously.com
Subject: Re: Getting pk of the most recent row, in a group by
In-Reply-To: <a55915760708131316t4ae9e506i3980e4ad87a8268c@mail.gmail.com>
* Save the following mbox file, import it into your mail client,
and reply-to-all from there: mbox
This inbox is served by DDX for PostgreSQL; see mirroring instructions
for how to clone and mirror all data and code used for this inbox