From: Lee Harr <missive@frontiernet.net>
To: pgsql-sql@postgresql.org
Subject: Re: Diffcult query
Date: Sat, 22 Mar 2003 03:59:18 +0000 (UTC)
Message-ID: <b5gn2l$1s2o$2@news.hub.org> (raw)
References: <d9Iea.117330$JE5.48428@news2.central.cox.net>
In article <d9Iea.117330$JE5.48428@news2.central.cox.net>, Dan Winslow wrote:
> Hi folks. This is giving me fits. I feel like it oughta be simple, but
> apparantly its not...I think.
>
> Given a table :
>
> create table tablea (
> code1 varchar(32),
> code2 varchar(32),
> cost int
> );
>
> and the rows
>
> code1 code2 cost
> ----------------------------------
> "aaa" "bbb" 2
> "ddd" "eee" 3
> "bbb" "aaa" 6
> "ggg" "hhh" 4
>
> I need a ( preferably single ) query that will sum the costs for all unique
> pairs of codes, without regard to column order. That is, for summing
> purposes, rows 1 and 3 are identical, and should produce the sum of 8 for
> the unordered pair("aaa","bbb"). It should also, of course, prevent the case
> where ("bbb","aaa") is considered a seperate pair. Any ideas would be much
> appreciated.
>
>
Maybe you could create a function that will return all of the rows
with a particular pair of codes.
Then I think you could GROUP BY that function...
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To: pgsql-sql@postgresql.org
Cc: missive@frontiernet.net
Subject: Re: Diffcult query
In-Reply-To: <b5gn2l$1s2o$2@news.hub.org>
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