From: Cris Carampa <cris119@operamail.com>
To: pgsql-sql@postgresql.org
Subject: where clause on a left outer join
Date: Wed, 22 Sep 2004 11:08:22 +0200
Message-ID: <cirfem$75c$1@floppy.pyrenet.fr> (raw)
Hello, let's suppose I have the following tables:
create table parent (
parent_id numeric primary key,
parent_data text
) ;
create table stuff (
stuff_id numeric primary key,
parent_id numeric references parent,
stuff_data text
) ;
And the following data:
crisdb=> select * from parent;
parent_id | parent_data
-----------+-------------
1 | aaa
2 | bbb
3 | ccc
(3 rows)
crisdb=> select * from stuff;
stuff_id | parent_id | staff_data
----------+-----------+------------
1 | 1 | xxx
2 | 1 | yyy
3 | 1 | zzz
(3 rows)
I wish to write a query that returns all rows from "parent" and, beside
of them, staff data with stuff_id=1 if available, otherwise null.
The following query:
select
par.parent_id,
stu.stuff_data
from
parent par left outer join stuff stu
on (
par.parent_id = stu.parent_id
)
where
stu.stuff_id = 1
;
Gives the following result:
parent_id | stuff_data
-----------+------------
1 | xxx
(1 row)
But this is not what I want.
The following query:
select
par.parent_id,
stu.stuff_data
from
parent par
left outer join
(
select
*
from
stuff
where
stuff_id = 1
) stu
on (
par.parent_id = stu.parent_id
)
;
Gives the following result:
parent_id | stuff_data
-----------+------------
1 | xxx
2 |
3 |
(3 rows)
Which is exacly what I want.
I'm wondering whether there is another way to get this result, without
using the online view.
Thank you. Kind regards,
--
Cris Carampa (spamto:cris119@operamail.com)
I got some John Coltrane on the stereo baby make it feel all right
I got some fine wine in the freezer mama I know what you like
I said a man works hard all day he can do what he wants to at night
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To: pgsql-sql@postgresql.org
Cc: cris119@operamail.com
Subject: Re: where clause on a left outer join
In-Reply-To: <cirfem$75c$1@floppy.pyrenet.fr>
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