From: Scott Marlowe <scott.marlowe@gmail.com>
To: John Lister <john.lister-ps@kickstone.com>
Cc: pgsql-sql@postgresql.org
Subject: Re: Partitioning by letter question
Date: Fri, 29 Jan 2010 16:50:31 -0700
Message-ID: <dcc563d11001291550j70867455q2f16fdf3a4a9cc4@mail.gmail.com> (raw)
In-Reply-To: <4B636022.90804@kickstone.com>
References: <4B636022.90804@kickstone.com>
On Fri, Jan 29, 2010 at 3:24 PM, John Lister
<john.lister-ps@kickstone.com> wrote:
> Hi, I was wondering if this was possible. I'm trying to partition a table,
> which is straightforward enough thanks to the great documentation, but i
> have a question:
>
> If I partition using something like a product_id for example and have check
> constraints such as (id>=1000 and id<2000) then everything is fine and the
> planner correctly uses the right subset of the tables. However I would like
> to partition by the first letter and using something like this
> substr(word,1,1)='a' is ignored by the planner. From reading the docs I
> understand that complicated check constraints are ignored, but this doesn't
> seem overly complicated.
>
> Am i doing something wrong or is there another better way to do this
Have you tried:
(word >= 'a' and word <'b')
?
Reply instructions:
You may reply publicly to this message via plain-text email
using any one of the following methods:
* Reply to all the recipients using the --to and --cc options:
reply via email
To: pgsql-sql@postgresql.org
Cc: scott.marlowe@gmail.com, john.lister-ps@kickstone.com
Subject: Re: Partitioning by letter question
In-Reply-To: <dcc563d11001291550j70867455q2f16fdf3a4a9cc4@mail.gmail.com>
* Save the following mbox file, import it into your mail client,
and reply-to-all from there: mbox
This inbox is served by DDX for PostgreSQL; see mirroring instructions
for how to clone and mirror all data and code used for this inbox