From: Joseph Shraibman <jks@selectacast.net>
To: pgsql-sql@postgresql.org
Subject: sorting by day of the week
Date: Tue, 24 Jan 2006 20:23:50 -0500
Message-ID: <dr6jv0$emi$2@news.hub.org> (raw)
p8:owl=>SELECT to_char( logtime, 'Dy'),count(*) FROM logtab WHERE
date_trunc('day', logtime) > current_date + '7 day ago'::interval group
by to_char( logtime, 'Dy') ORDER BY to_char( logtime, 'Dy') DESC;
to_char | count
---------+-------
Wed | 1447
Tue | 618
Thu | 1161
Sun | 230
Sat | 362
Mon | 760
Fri | 1281
(7 rows)
The problem is that I want those results sorted in day of week order,
not text order of the day name, so I tried this:
p8:owl=>SELECT to_char( logtime, 'Dy'),count(*) FROM sclog WHERE
date_trunc('day', logtime) > current_date + '7 day ago'::interval group
by to_char( logtime, 'Dy') ORDER BY to_char( logtime, 'D') DESC;
ERROR: column "sclog.logtime" must appear in the GROUP BY clause or be
used in an aggregate function
Now obviously I don't want to group by logtime (a timestamp) so how do I
work around this? What I really need is a function that converts from
the char representation to a day of week number or vice versa. I also
have the same problem with month names.
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To: pgsql-sql@postgresql.org
Cc: jks@selectacast.net
Subject: Re: sorting by day of the week
In-Reply-To: <dr6jv0$emi$2@news.hub.org>
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