From: 荒井元成 <n2029@ndensan.co.jp>
To: 'Tom Lane' <tgl@sss.pgh.pa.us>
To: 'Holger Jakobs' <holger@jakobs.com>
Cc: pgsql-admin@lists.postgresql.org
Subject: RE: About Unicode IVS
Date: Tue, 29 Mar 2022 20:03:45 +0900
Message-ID: <013501d8435c$a8f1c9e0$fad55da0$@ndensan.co.jp> (raw)
In-Reply-To: <1107956.1648549556@sss.pgh.pa.us>
References: <00e201d8431c$cb38eb40$61aac1c0$@ndensan.co.jp>
<CAKFQuwYCTmp5t5_7n+qRoKZArnBvv309CSi4XVdONXxQL6OX0Q@mail.gmail.com>
<00f601d84326$5367cf00$fa376d00$@ndensan.co.jp>
<006501d84350$37bae6f0$a730b4d0$@msym.fr>
<012c01d84353$1f8a8d30$5e9fa790$@ndensan.co.jp>
<15e893e2-1237-27f4-58ba-5ea59499fa3d@jakobs.com>
<1107956.1648549556@sss.pgh.pa.us>
thank you for your reply.
In SQL Server, the variant character selector is treated as one character with two characters. The collation order is Japanese_XJIS_140_CS_AS_KS_WS_VSS_UTF8.
Moto.
-----Original Message-----
From: Tom Lane <tgl@sss.pgh.pa.us>
Sent: Tuesday, March 29, 2022 7:26 PM
To: Holger Jakobs <holger@jakobs.com>
Cc: pgsql-admin@lists.postgresql.org; n2029@ndensan.co.jp
Subject: Re: About Unicode IVS
Holger Jakobs <holger@jakobs.com> writes:
> It's totally correct that the two characters are still two characters.
> You would have to normalize the string first, so that the combination
> becomes one character.
Yeah. In principle the normalize() function ought to do this for you. But it doesn't seem to shorten the given example for me; I'm not sure if that means the example is incorrect, or if it's a bug in normalize().
u8=# select octet_length(U&'\+008FBA' || U&'\+0E0102'); octet_length
--------------
7
(1 row)
u8=# select octet_length(normalize(U&'\+008FBA' || U&'\+0E0102')); octet_length
--------------
7
(1 row)
regards, tom lane
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Subject: RE: About Unicode IVS
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