From: will trillich <will@serensoft.com>
To: pgsql-general@postgresql.org
Subject: Re: Var substitution in SELECT statements
Date: Tue, 24 Apr 2001 02:15:16 -0500
Message-ID: <20010424021516.I27356@serensoft.com> (raw)
In-Reply-To: <B70A521F.A291%rgp@systame.com>
References: <B70A4D23.A28D%rgp@systame.com>
<B70A521F.A291%rgp@systame.com>
On Mon, Apr 23, 2001 at 09:41:51PM -0400, Randall Perry wrote:
> on 4/23/01 9:20 PM, Randall Perry at rgp@systame.com wrote:
>
> > This works:
> > $res = $conn->exec("select cust, contact, user_name, email from $t where
> > user_name = a1a");
> >
> > This doesn't:
> > $c = "a1a";
> > $res = $conn->exec("select cust, contact, user_name, email from $t where
> > user_name = $c");
> >
> > and returns the error:
> > Attribute 'a1a' not found
> >
> >
> > How do you do var substitution with the Pg module in Perl?
>
> Whoops! Needed to quote the var as so (for $c above):
>
> $c = "\'$c\'";
>
> Works now.
also try
$sth = $dbh->prepare("select fields from tbl where f1 = ? and f2 = ?")
$sth->execute($val1,$val2);
while ($ref = $sth->fetchrow_hashref()) {
...
}
$sth->finish();
--
don't visit this page. it's bad for you. take my expert word for it.
http://www.salon.com/people/col/pagl/2001/03/21/spring/index1.html
will@serensoft.com
http://sourceforge.net/projects/newbiedoc -- we need your brain!
http://www.dontUthink.com/ -- your brain needs us!
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To: pgsql-interfaces@postgresql.org
Cc: will@serensoft.com, pgsql-general@postgresql.org
Subject: Re: Var substitution in SELECT statements
In-Reply-To: <20010424021516.I27356@serensoft.com>
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