pg.ddx.io  pgsql-sql@postgresql.org mailing list archive  
help / color / mirror / Atom feed
From: Stephan Szabo <sszabo@megazone.bigpanda.com>
To: Joost Kraaijeveld <J.Kraaijeveld@Askesis.nl>
Cc: Pgsql-sql@postgresql.org <Pgsql-sql@postgresql.org>
Subject: Re: How to get a count() where column < ''?
Date: Sun, 4 Dec 2005 14:29:16 -0800 (PST)
Message-ID: <20051204142347.R57404@megazone.bigpanda.com> (raw)
In-Reply-To: <1133732596.5560.11.camel@Panoramix>
References: <1133730772.5560.8.camel@Panoramix>
	<20051204133233.O57404@megazone.bigpanda.com>
	<1133732596.5560.11.camel@Panoramix>


On Sun, 4 Dec 2005, Joost Kraaijeveld wrote:

> Hi Stephan,
>
> On Sun, 2005-12-04 at 13:33 -0800, Stephan Szabo wrote:
> > > SELECT COUNT(customers.objectid) FROM prototype.customers,
> > > prototype.addresses
> > > WHERE
> > > customers.contactaddress = addresses.objectid
> > > AND
> > > zipCode < '2716BN'
> > > ORDER By zipCode, houseNumber
>
> > In a non-grouped query like the above, I don't think that the order by is
> > meaningful.  You only get one row back anyway without a group by, and
> > there's no single zipCode or houseNumber to associate with the row.
> >
> What do you mean by a non-grouped query? The query below gives the same
> error:

A query without a group by, in other words one on which the count is done
over the entire set of rows that pass the where clause.

> SELECT zipcode, COUNT(*) FROM prototype.customers, prototype.addresses
> WHERE
> customers.contactaddress = addresses.objectid
> AND
> zipCode < '2716BN'

Yes, because without a group by there's one count and it has no associated
zipcode to put in the select list.

I believe
 select count(*) from prototype.customers, prototype.addresses where
 customers.contactaddress = addresses.objectid and zipCode < '2716BN';
will work and give you an overall count.

 select zipcode, count(*) from prototype.customers, prototype.addresses
 where customers.contactaddress = addresses.objectid and zipCode <
 '2716BN' group by zipcode order by zipcode;
should give you a list broken up with a count by zipcode in order of
zipcode.



view thread (6+ messages)  latest in thread

Message-ID: <20051204142347.R57404@megazone.bigpanda.com>
Permalink:  ../20051204142347.R57404@megazone.bigpanda.com/
Also on:    postgresql.org/message-id/20051204142347.R57404@megazone.bigpanda.com

 · 

reply

Reply instructions:

You may reply publicly to this message via plain-text email
using any one of the following methods:

* Reply to all the recipients using the --to and --cc options:
  reply via email

  To: pgsql-sql@postgresql.org
  Cc: sszabo@megazone.bigpanda.com, J.Kraaijeveld@Askesis.nl
  Subject: Re: How to get a count() where column < ''?
  In-Reply-To: <20051204142347.R57404@megazone.bigpanda.com>

* Save the following mbox file, import it into your mail client,
  and reply-to-all from there: mbox

This inbox is served by DDX for PostgreSQL; see mirroring instructions
for how to clone and mirror all data and code used for this inbox