From: Jim Buttafuoco <jim@contactbda.com>
To: 'Bryce Nesbitt' <bryce1@obviously.com>
To: pgsql-sql@postgresql.org
Subject: Re: Doing a conditional aggregate (e.g. count(*) if x=y) in postgres?
Date: Mon, 14 May 2007 19:16:14 -0400
Message-ID: <200705142316.l4ENGGS4010065@contactbda.com> (raw)
In-Reply-To: <4648E8F1.4020609@obviously.com>
Use case statement and sum to get a count where status=20...
For example
Select sum(case when status=20 then 1 else 0 end) as status20,
Sum(case when status=30 then 1 else 0 end) as status30
....
-----Original Message-----
From: pgsql-sql-owner@postgresql.org [mailto:pgsql-sql-owner@postgresql.org]
On Behalf Of Bryce Nesbitt
Sent: Monday, May 14, 2007 6:56 PM
To: pgsql-sql@postgresql.org
Subject: [SQL] Doing a conditional aggregate (e.g. count(*) if x=y) in
postgres?
All;
Is there a way to get a conditional aggregate? I have this two column view:
SELECT count(*) AS count, xx_plan.plan_name
FROM xx_membership
JOIN xx_account USING (account_id)
JOIN xx_plan USING (plan_id)
WHERE xx_membership.status = 10
GROUP BY xx_plan.plan_name;
And would like to add additional columns (not rows) breaking out
"status=20" and "status=30" totals.
Is this possible without a stored procedure?
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To: pgsql-sql@postgresql.org
Cc: jim@contactbda.com, bryce1@obviously.com
Subject: Re: Doing a conditional aggregate (e.g. count(*) if x=y) in postgres?
In-Reply-To: <200705142316.l4ENGGS4010065@contactbda.com>
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