From: Larry Lennhoff <llennhoff-postgres@pexicom.com>
To: Tom Lane <tgl@sss.pgh.pa.us>
Cc: pgsql-sql@postgresql.org
Subject: Re: Create interval using column value?
Date: Sun, 24 Oct 2004 23:18:55 -0400
Message-ID: <6.0.2.0.0.20041024231819.03b5c540@localhost> (raw)
In-Reply-To: <9636.1098673912@sss.pgh.pa.us>
References: <6.0.2.0.0.20041024224504.03b5c7c8@localhost>
<9636.1098673912@sss.pgh.pa.us>
Thanks, that was exactly what I needed.
Larry
]At 11:11 PM 10/24/2004, Tom Lane wrote:
>Larry Lennhoff <llennhoff-postgres@pexicom.com> writes:
> > What I want to do is find all the rows in
> > A which were built before now() - build_interval seconds ago. If I could
> > just write this in SQL it would look something like:
>
> > SELECT A.id FROM A JOIN B ON (join_col) WHERE built_on < now() - interval
> > 'build_interval seconds';
>
>You are confused about the difference between a literal constant and an
>expression. Try something like
>
>.. WHERE built_on < now() - build_interval * interval '1 second';
>
>which relies on the number-times-interval operator.
>
> regards, tom lane
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To: pgsql-sql@postgresql.org
Cc: llennhoff-postgres@pexicom.com, tgl@sss.pgh.pa.us
Subject: Re: Create interval using column value?
In-Reply-To: <6.0.2.0.0.20041024231819.03b5c540@localhost>
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