From: Tom Lane <tgl@sss.pgh.pa.us>
To: Larry Lennhoff <llennhoff-postgres@pexicom.com>
Cc: pgsql-sql@postgresql.org
Subject: Re: Create interval using column value?
Date: Sun, 24 Oct 2004 23:11:52 -0400
Message-ID: <9636.1098673912@sss.pgh.pa.us> (raw)
In-Reply-To: <6.0.2.0.0.20041024224504.03b5c7c8@localhost>
References: <6.0.2.0.0.20041024224504.03b5c7c8@localhost>
Larry Lennhoff <llennhoff-postgres@pexicom.com> writes:
> What I want to do is find all the rows in
> A which were built before now() - build_interval seconds ago. If I could
> just write this in SQL it would look something like:
> SELECT A.id FROM A JOIN B ON (join_col) WHERE built_on < now() - interval
> 'build_interval seconds';
You are confused about the difference between a literal constant and an
expression. Try something like
... WHERE built_on < now() - build_interval * interval '1 second';
which relies on the number-times-interval operator.
regards, tom lane
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To: pgsql-sql@postgresql.org
Cc: tgl@sss.pgh.pa.us, llennhoff-postgres@pexicom.com
Subject: Re: Create interval using column value?
In-Reply-To: <9636.1098673912@sss.pgh.pa.us>
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