From: Wes James <comptekki@gmail.com>
To: pgsql-sql@postgresql.org
Subject: Re: sum an alias
Date: Fri, 4 Jun 2010 07:30:18 -0600
Message-ID: <AANLkTilYVcqa-2exe48IhvV-HSEcWKFSAO1B03hsoBtG@mail.gmail.com> (raw)
In-Reply-To: <20100604055434.GA19411@a-kretschmer.de>
References: <AANLkTil0i1cg1DulN4sIEIa08qM5VU5VuLoKB7u8g1-D@mail.gmail.com>
<20100604055434.GA19411@a-kretschmer.de>
On Thu, Jun 3, 2010 at 11:54 PM, A. Kretschmer
<andreas.kretschmer@schollglas.com> wrote:
> In response to Wes James :
>> In the statement:
>>
>> select
>> MAX(page_count_count) - MIN(page_count_count) as day_tot,
>> MAX(page_count_count) as day_max, sum(MAX(page_count_count) -
>> MIN(page_count_count)) as tot,
>> page_count_pdate
>> from page_count
>> group by page_count_pdate order by page_count_pdate
>>
>> Is there a way to do sum(day_tot) also in the same statement?
>
> Is this the correct table-definition?
>
> test=# \d page_count
> Table "public.page_count"
> Column | Type | Modifiers
> ------------------+---------+-----------
> page_count_pdate | date |
> page_count_count | integer |
That is the correct table def.
> If yes, your SQL is wrong:
I know the sql is wrong - I should have mentioned that, but I'm
looking for something that will work like that. I need to sum the
difference of max() - min((). How can this be done, since there
doesn't seem to be a way to sum aggregates.
>
> test=# select
> MAX(page_count_count) - MIN(page_count_count) as day_tot,
> MAX(page_count_count) as day_max, sum(MAX(page_count_count) -
> MIN(page_count_count)) as tot,
> page_count_pdate
> from page_count
> group by page_count_pdate order by page_count_pdate;
> ERROR: aggregate function calls cannot be nested
> LINE 3: MAX(page_count_count) as day_max, sum(MAX(page_count_cou...
>
>
> Can you provide the correct table definition?
thx,
-wes
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To: pgsql-sql@postgresql.org
Cc: comptekki@gmail.com
Subject: Re: sum an alias
In-Reply-To: <AANLkTilYVcqa-2exe48IhvV-HSEcWKFSAO1B03hsoBtG@mail.gmail.com>
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