From: Rodrigo De Leon <rdeleonp@gmail.com>
To: pgsql-sql@postgresql.org
Subject: Re: CREATE TABLE AS inside of a function
Date: Fri, 21 Jul 2006 14:32:07 -0600
Message-ID: <a55915760607211332ye89afd4m9bb2ad456fcef99b@mail.gmail.com> (raw)
In-Reply-To: <6EA72AC41F81D242A38AAF505523A94D022DF6@kappa.acrodex.net>
References: <6EA72AC41F81D242A38AAF505523A94D022DF6@kappa.acrodex.net>
On 7/21/06, Kevin Nikiforuk <Kevin.Nikiforuk@acrodex.com> wrote:
> So now that I've got my loops working, on to my next newbie question. I've created my function and in it, I want to loop through the results of a select and for each value of my loop counter, I want to create a new table, but I can't figure out how to use a variable in the name of the new table, see below.
>
> CREATE OR REPLACE FUNCTION rgio() RETURNS INTEGER as $$
> DECLARE
> lv RECORD;
>
> BEGIN
> FOR lv IN SELECT DISTINCT rg FROM ldevrg LOOP
> CREATE TABLE rgio_$lv AS
> SELECT ldev
> FROM ldevrg
> WHERE rg='$lv';
> END LOOP;
> RETURN 1;
> END;
> $$ LANGUAGE plpgsql;
>
> Thanks,
> Kevin
See:
http://www.postgresql.org/docs/8.1/static/plpgsql-statements.html#PLPGSQL-STATEMENTS-EXECUTING-DYN
Regards,
Rodrigo
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To: pgsql-sql@postgresql.org
Cc: rdeleonp@gmail.com
Subject: Re: CREATE TABLE AS inside of a function
In-Reply-To: <a55915760607211332ye89afd4m9bb2ad456fcef99b@mail.gmail.com>
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